3g^2-3g=3

Solution for 3g^2-3g=3 equation:

3g^2-3g=3

We move all terms to the left:

3g^2-3g-(3)=0

a = 3; b = -3; c = -3;
Δ = b2-4ac
Δ = -32-4·3·(-3)
Δ = 45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{45}=\sqrt{9*5}=\sqrt{9}*\sqrt{5}=3\sqrt{5}$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{5}}{2*3}=\frac{3-3\sqrt{5}}{6}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{5}}{2*3}=\frac{3+3\sqrt{5}}{6}
$